An iron ball of density 7.8 g/cm³ and volume 200 cm³ is totally immersed in water.Calculate the up thrust on it.
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Answered by
43
upthurst force = vdg
where v = volume of iron ball = 200*10^-6 m³
d = density of water = 1000kg/m³
g = gravitational force = 9.8 m/s²
upthurst force = 200*10^-6*1000*9.8
= 1.96N
where v = volume of iron ball = 200*10^-6 m³
d = density of water = 1000kg/m³
g = gravitational force = 9.8 m/s²
upthurst force = 200*10^-6*1000*9.8
= 1.96N
Answered by
23
When a body is immersed in a liquid, the upthrust is
F = ρvg
here;
liquid is water, so ρ=1000 kg/m³
volume, v = 200 cm³ = 200×10⁻⁶ m³
g = 9.8 m/s²
Upthrust, F = ρvg = 10³ × (200×10⁻⁶) × 9.8 = 1.96 N
F = ρvg
here;
liquid is water, so ρ=1000 kg/m³
volume, v = 200 cm³ = 200×10⁻⁶ m³
g = 9.8 m/s²
Upthrust, F = ρvg = 10³ × (200×10⁻⁶) × 9.8 = 1.96 N
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