Question

An iron ball of mass 0.2 kg is heated to 10 degree celsius and put into a block of ice at 0 degree celsius 25 gram of ice melts if latent heat of fusion of ice is 80 cal /g then specific heat of iron is

Answer 1

specific heat of iron is 238.095 J/Kg/°C

An iron ball of mass , M = 0.2 kg is heated to 10°C and put into a block of ice at 0°C, m = 25g of ice melts.

heat absorbed by iron ball, Q = Ms∆T

= 0.2 × s × 10

= 2s ........(1)

heat gained by ice to melt it, Q' = mL_f

= 25g × 80cal/g

= 25 × 80 cal

we know, 1 cal = 4.2 Joule

so, Q' = 25 × 80/4.2 = 476.19 J

heat gained = heat lost

⇒Q = Q'

⇒2s = 476.19 J

⇒s = 476.19/2 = 238.095 J/Kg/°C

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