Question

an iron ball of mass 3kg is release from a height of 125m and fall freely to the ground assuming that the value of g is 10m/ second square calculate vilocity of ball reaching the ground the height of the ball at half the time it takes to reach the ground
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Answer 1

Answer:

50m/sec, 31.25m.

Explanation:

Velocity of the ball when it reaches ground =

V^2 -U^2 = 2aS

V = √2(10)(125)

V = 50m/sec.

Height of the ball at half the time it takes to reach the ground =

S1/S2 = t1^2/t2^2

125/S2 = 4t1^2/t1^2 (t2=t1/2)

S2 = 125/4

S2 = 31.25m