Question

An iron ball of mass 9 kg is placed at one end of the lever at a distance of 5m from point o (fulcrum). The length of lever is 20m . The effort is to be given at other end to loft the ball

Answer 1

If we increase slightly above 2.25 kg it will loft the ball.

Given:

An iron ball of mass 9 kg is placed at one end of the lever at a distance of 5m from point o (fulcrum).

The length of lever is 20m .

To find:

The effort is to be given at other end to loft the ball.

Formula used:

Moment = mass×Distance

Explanation:

The effort required to loft the ball will be calculated by equating the moment of mass and effort from the point o (fulcrum).

Iron ball mass= 9kg  distance from fulcrum = 5m

Distance of effort from fulcrum= 20m

Moment of mass = moment of effort applied.

                9×5 = 20 × Effort

                Effort = $\frac{9\times 5 }{20}$ = 2.25 kg.

If we increase slightly above 2.25 kg it will loft the ball.

To learn more....

1)One of the effect of a force is to change the momentum define the quantity related to this and explain it for a variable force usually when do we define it instead of using the force ​

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2)The momentum of a body increase from 150kg-m/s to 600 kg-m/s in 2 minutes . calculate applied force on a body.

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