An iron ball requires 1000 J
heat to raise
is
1 An
a
temperature by 20°c. Calulate the heat capacity
of the ball .
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Answer:
Given
Heat Require=1000 J
change in Temperature=20 ^{\circ}c=20
∘
c
and we know
heat transferred is Q=C\Delta TQ=CΔT
Where C=heat capacity
1000=C\times 201000=C×20
C=50 J/^{\circ}cC=50J/
∘
c
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