Question

An iron ball requires 1000 J of heat to raise its temperature by 20 degrees Celsius. Calculate the heat capacity of the ball

Answer 1

Answer:$C=50 J/^{\circ}c$

Explanation:

Given

Heat Require=1000 J

change in Temperature$=20 ^{\circ}c$

and we know

heat transferred is $Q=C\Delta T$

Where C=heat capacity

$1000=C\times 20$

$C=50 J/^{\circ}c$

Answer 2

Answer:

Q=1000 J

∆T=20°C=20K

specific heat capacity C=?

Solution:

C=Q/∆T=1000/20=50J/K

=50J/K-1