Question

An iron ball requires 1000 J of heat to raise its temperature by 20°c. Calculate the heat capacity of the ball ​

Answer 1

Heat Energy = 1000J

raise the temperature by = 20°C

Heat capacity = 1000J / 20°C

=> 50 Joules per °Celcius

Answer 2

Answer:

50 J/° C

Step-by-step explanation:

Heat required to raise the temperature by 20° C ---> 1000 J

Δt (change in temperature) ---> 20° C

Now, C = Q/Δt (C denotes the heat capacity of a substance; Q denotes the heat given; Δt denotes the change in temperature)

=> C = 1000 J/20° C => 50 J/° C

Thus, heat capacity of this particular ball is 50J/° C.