Question

An iron ball requires 1000j of heat to raise its temperature by 20degree c calculate the heat capacity of the ball

Answer 1

Answer:

100JK^-1

Explanation:

Heat capacity, C' = Q/delta T

Here, Q = 1000J

Delta T= 20°C - 10°C =10°c = 10K

C' = 1000/10 = 100JK^-1

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