An iron block of dimensions 5 cm X 10 cm X 15 cm has to be pushed along the floor. The force required will
be minimum when the surface in contact with ground is
A. (10 cm X 15 cm) surface B. (5 cm X 15 cm) surface
C. (10 cm X 5 cm) surface D. force is same for all surfaces
Answers
Answered by
13
HOLA!!
HERE YOUR ANSWER IS
C) (10cm×5cm) surface.
REASON:
we know that pressure = force /area
then force = pressure × area
this shows that force is directly proportional to area.
now 10cm ×15 cm = 150cm^-2
5 cm×15 cm = 75 cm^-2
10cm × 5cm = 50cm^-2
we need minimum force so we should choose surface with minimum area that is (10cm×5cm).
HOPE MY ANSWER HELPS YOU!!
HERE YOUR ANSWER IS
C) (10cm×5cm) surface.
REASON:
we know that pressure = force /area
then force = pressure × area
this shows that force is directly proportional to area.
now 10cm ×15 cm = 150cm^-2
5 cm×15 cm = 75 cm^-2
10cm × 5cm = 50cm^-2
we need minimum force so we should choose surface with minimum area that is (10cm×5cm).
HOPE MY ANSWER HELPS YOU!!
Answered by
7
The answer is C as C has the smallest surface area.Thus,frictional force is smallest,less force is needed to move the iron block is minimum
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