Physics, asked by manjula3ds, 4 months ago

An iron box of resistance 60 ohm takes current of 3 amp. Find heat developed in 20 sec





pls ans soon.......​

Answers

Answered by Anonymous
74

━━━━━━━━━━━━━━━━━━━━━━━━

 \small \underline \bold{For \: an \: iron \: box}:-

 \large \underline \bold{Given}:-

\: \: \: \: \: \: \: \sf{resistance \: (R) \: = \: 60}Ω

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{Current \: (I) \: = \: 3 \: A}

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{time \: (t) \: = \: 20 \: second}

 \large \underline \bold{To \: Find}:-

\sf{what's \: the \: developping \: heat \: by \: the \: iron \: box \: ?}

 \large \underline \bold{Usable \: Formula}:-

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:  \large\boxed{\sf\pink{H \: = \: I^{2} R t}}

\sf{here \: ,}

\: \: \: \: \: \: \: \: \sf{H \: = \: developping \: heat \: (in \: joule)}

\: \: \: \: \: \: \: \: \: \: \sf{I \: = \: Current \: (In \: ampere)}

\: \: \: \: \: \: \: \: \sf{R \: = \: resistance \: (in \: ohm)}

\: \: \: \: \: \: \: \: \: \sf{t \: = \: time \: (in \: second)}

 \large \underline \bold{Solution}:-

\sf{On \: Using \: the \: above \: formula \: -}

\: \: \: \: \: \: \: \: \: \:  \small \bold{H \: = \: I^{2} R t}

\: \: \: \: \: \: \: \: \: \: \sf{H \: = \: (3)^{2}\times 60\times 20}

\: \: \: \: \: \: \: \: \: \: \sf{H \: = \: 9\times 60\times 20}

\: \: \: \: \: \: \: \: \: \: \sf{H \: = \: 9\times 12\times 100}

\: \: \: \: \: \: \: \: \: \: \sf{H \: = \: 108\times 100}

\: \: \: \: \: \: \: \: \: \: \sf{H \: = \: 10800 \: J}

\: \: \: \: \: \: \:  \large \bold{H \: = \: 10.8 \: KJ}

━━━━━━━━━━━━━━━━━━━━━━━━

Similar questions