Math, asked by fnazneen2d, 1 year ago

An iron cone of diameter 8cm and height 12cm is melted and recast into spherical iron shots each of radius 4mm. How many shots are made?

Answers

Answered by ExoticExplorer
22

diameter of right circular cone = 8 cm

radius of right circular cone (r) = 4 cm

Height of right circular cone (h) = 12 cm

Radius of spherical lead shot (r) = 4 mm

                      10 mm = 1 cm

                       4 mm = (4/10) cm  

Volume of right circular cone = n x (Number of spherical lead shots)

                      n = Volume of cone/Number of spherical lead shots

                             n =  (1/3)Π r² h/(4/3)Π r³

                             n =  (1/3) (4)² (12) x (3/4) (10/4)³

                             n =  (1/3) x 4 x 4 12 x (3/4) x (10/4) x (10/4) x (10/4)

                             n =  3 x 5 x 10

                             n = 750 lead shots 

Therefore 750 lead shots can be made.

Hope This Helps :)


fnazneen2d: Thanks a lot!!
ExoticExplorer: Uh r always welcome :)
Answered by brindamanoharan
5

Answer:

Step-by-step explanation:

diameter of right circular cone = 8 cm

radius of right circular cone (r) = 4 cm

Height of right circular cone (h) = 12 cm

Radius of spherical lead shot (r) = 4 mm

                     10 mm = 1 cm

                      4 mm = (4/10) cm  

Volume of right circular cone = n x (Number of spherical lead shots)

                     n = Volume of cone/Number of spherical lead shots

                            n =  (1/3)Π r² h/(4/3)Π r³

                            n =  (1/3) (4)² (12) x (3/4) (10/4)³

                            n =  (1/3) x 4 x 4 x 12 x (3/4) x (10/4) x (10/4) x (10/4)

                            n =  3 x 5 x 5 x 10

                            n = 750 lead shots 

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