Question

An iron core solenoid has self inductance 2.8H.when the core is removed the self inductance becones 2mH.what is the relative permeability of core used?​

Answer 1

Explanation:

Given An iron core solenoid has self inductance 2.8 H.when the core is removed the self inductance becomes 2mH.what is the relative permeability of core used?

• Now initial inductance Li = μo μr n^2 Al
• After removal of solenoid inductance will be La = μo n^2 Al
• Now Li / La = μo μr n^2 Al / μo n^2 Al
• Or  Li / La = μr (relative permeability)
• So 2.8 / 2 x 10^-3 = μr

Or μr = 1400

Reference link will be

https://brainly.in/question/11151203

Answer 2

Explanation:

Li/La = mew r

so 2.8 /2 ×10^-3=1400mew r