Question

An iron-core transformer operating from a 120-V line has 500 turns in the primary and 100 turns in the secondary. Find the secondary voltage.​

Answer 1

Answer:

WFirst we use the fact that the ratio of the voltage on the secondary and on the primary will be the same as the ratio of the number of turns of both coils,

⇒u=

u

1

u

2

=

N

1

N

2

We evaluate the unkown secondary voltage -

⇒u

2

=

N

1

N

2

u

1

We substitute the given values -

⇒u

2

=

500

10

×120v=2.4v

Hence, the answer is 2.4v.

Answer 2

Explanation:

we know

transformer equation

V1 /V2=ñ2/ñ1

so 120/v=100/500

so v=120x5

v=600volt

secondary voltage=600v