An iron cube has a mass of 480g and density of 8g/cm³ is suspended by a string so that it is half immased in an oil of density of 0.9g/cm³ find the tension on the string
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Answer:
Explanation:
480/8) = volume of 60cc., so it will displace (60/2) = 30cc. of oil when half immersed.
(30 x 0.9) = mass of 27g. oil displaced.
(480g - 27g) = 453g., or 0.453kg.
(0.453 x 9.8) = tension of 4.4N. in string.
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