Question

an iron cube of dimensions 5 cm is heated at 200°C calculate change in volume idf cofficient of cubical expansion of iron is 3.6 *10*5 °C​

Answer 1

Answer:

The diameter of (d) of iron tyre should be equal to ⊥m i.e., 1000 mm

The initial diameter (d) of iron tyre

=1m−6mm

=(1000−6)mm

=994 mm

we have

cubical expressin (

r

ˉ

)=3.6×10

−5

/

o

C

⇒ 3α=3.6×10

−5

⇒ α=1.2×10

−5

/

o

C

where

α→linear expression

Now, we know that

l=l

0

(⊥+αΔθ)

there,

d=d

0

(⊥+αΔθ)

1000=994(⊥+1.2+10

−5

Δθ)

⇒994×1.2×10

−5

Δθ=6

⇒ Δθ=

994×1.2

6

×10

5

=503

o

C

⇒ Δθ≅500

o

C