an iron cube of side 10 cm is kept on a horizontal table. if the density of iron is 8000kg/m*3, find the pressure on the portion of the table where the cube is kept (g=10m/s*2)
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Given : density = 8000kg/m*3
Side of the cube = 10cm =0.1m
Area of the cube = 6 × (0.1)^2
=6×10^-2
Density = mass / volume
Mass = density × volume
Mass = 8000 × (0.1)^3
Mass = 8kg
Force = mass × acceleration
Here, acceleration = g = 10m/s^2
Force = 8 × 10
Force = 80N
Pressure = Force / Area
Pressure = 80 / 6 ×10^-2
Pressure = 1,333.334Nm^-2 or Pa
Hope its clear for you.
[THANK YOU]
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