Question

An iron cube of side 10cm is kept in a horizontal table.if density of iron is 8000kg/m3,find the pressure on the portion of the table where the cube is kept.(g=10m/s2)

Answer 1

volum of the cube=1000cm3
mass of the iron cube=8000*10∧-3
=8kg
force=mg
f=80 N
p=f/a
p=80/100cm∧2
p=80/0.01m²
p=8000 N/m²

Answer 2

volume=0.1m*0.1m*0.1m=0.001m
density=mass/volume
mass=density*volume
mass=8kg(by calculation)
f=ma
f=8*10
=80N
p=f/a
  =80/0.001
  =8000 pa