an iron cube of side 10cm is kept on a horizontal table if the density of iron is 8000kg/m3 find the pressureon the portion of the table where the cube was kept . (g =10m/s2)
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side of the cube , a = 10 cm = 0.1 m
Volume of the cube, V = (0.1)3 = 0.001 m3
Density = 8000 kg /m3
Mass = Density x volume = 8000x(0.001) = 8 kg
Pressure = Force / area = (mg)/(0.1x0.1) = 8000 Pa.
Hope this will help you.... ✌
Volume of the cube, V = (0.1)3 = 0.001 m3
Density = 8000 kg /m3
Mass = Density x volume = 8000x(0.001) = 8 kg
Pressure = Force / area = (mg)/(0.1x0.1) = 8000 Pa.
Hope this will help you.... ✌
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