Question

An iron cube of side 10cm is kept on a horizontal table. If the density of iron is 8000kg/m3 , find the pressure on the portion of the table where the cube is kept.

Answer 1

$Area \: of \: a \: Square = {Side}^{2} \\ a = {10}^{2} \\ a = 100 {cm}^{2} or \: 0.01 {m}^{2} \\ \\ Density = \frac{Mass}{Volume} \\ 8000 = \frac{Mass}{0.001} \\ Mass = 8kg \\ \\ Force = mg \\ F = 8 \times 10 \\ F = 80N \\ \\ Pressure = \frac{Force}{Area} \\ P = \frac{80}{0.01} \\ Pressure = 8000 Pa$