Question

an iron cube of side 5 cm and of r d 7.6 is suspended by a thread in brine solution of relative density 1.2 find tension in thread




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Answer 1

Answer:

Volume of liquid displaced = Volume of metal cube = 125 x 10−6 m3. = 125 x 10−6 m3. 1200 kg/m3. Therefore tension in the string = 9.75 N.

Answer 2

Answer:

Volume of liquid displaced = Volume of metal cube = 125 x 10−6 m3. = 125 x 10−6 m3. 1200 kg/m3. Therefore tension in the string = 9.75 N.

Explanation:

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