An iron cuboid has volume 100cm3.Find its volume in S.I unit . step by step explain
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Apparent weight of iron = Weight of iron in air - weight of iron in water
As we know , Density =
volume
mass
So mass of iron piece in air = (volume) (density) =(10
−4
)(7800)kg=0.78kg
Weight of iron piece in air=mg=7.8N
weight of iron piece in water = upthrust = Vρg = 10
−4
(1000)10N=1N
so apparent weight of the iron piece =7.8N−1N=6.8N
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