Question

An iron cuboid of dimension 4cm,310cm,350cm and mass 4 kg is placed on a table.if the value of g is 10m/s2 then maximum and minimum pressure exerted by the iron cuboid on the surface of the table will be

Answer 1

for maximum pressure → area will be minimum
area minimum area = 4 × 310 cm²
= 1240 × 10-⁴ m²
= 0.124 m²

now, max pressure = F/A =ma/A
= 4× 10/0.124 = 40×10³/124 Pa
= 322.58 Pa

minimum pressure → maximum area
maximum area = 310 × 350 = 108500× 10-⁴ m² = 10.85 m²

so, min pressure = 40/10.85 = 3.6866 Pa