Question

An iron cylindrical rod has a height 4 times its radius is melted and cast into spherical balls of the same radius. The number of balls cast is ​

Answer 1

Explanation:

Radius of rod=r

so height=4r

radius of balls=r

No. of balls=volume of rod

volume of balls

= pi×r^2×h/4/3×pi×r^3

=3×r^2×4r/4×r^3

=12r^3/4r^3

=3

Answer 2

3 Balls

Explanation:

Given:

Radius of rod = r

Height of rod = h

Radius of sphere = r

We know that,

Volume of Cylinder rod = Volume of sphere x Number of balls (Given)

$\pi r^{2}h$  = 4/3 $\pi r^3$ x Number of balls

= 22/7 x r x r x 4r = 4/3 x 22/ 7 x r x r x r x Number of balls

4 = 4 / 3 Number of balls

= 3 = Number of sphere balls

Therefore, 3 sphere balls of same radius cast.

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