Question

An iron dealer sold a piece of 20m from a long iron pipe . Then the ratio of the sold part and the remaining parts become 5:2 . What was the original length of the pipe? Determine the ratio of the original length to the remaining part​

Answer 1

let total length of pipe be x metres

length of the remaining pipe = (x-20)m

A/Q

=> 20 : (x-20) :: 5 : 2

$= > \frac{20}{x - 20} = \frac{5}{2} \\ \\ = >40 = 5x - 100 \\ \\ = > x = \frac{140}{5} \\ \\ = > x = 28 \: m \\ \\ \\ ratio = \frac{original \: length}{remaining \: part} \\ \\ ratio \: = \frac{28}{8} = \frac{7}{2}$

original length of the pipe os 28 m and ratio of original length to the remaining length of the pipe is

7 : 2

Answer 2

Answer:

7:2..................