An iron is rated at 230 V, 750 W. What power would be supplied to it if it is used with a mains p.d of only 220 V? Assume that the resistance of the iron is constant.
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Answer:
POWER=740J
Explanation:
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Power = Voltage^2 / Resistance.
As resistance is given constant.
750 = 230 * 230 / Resistance
Resistance = 230 * 230 / 750
Resistance = 70.533
If it is used with mains potential difference of only 220 V then
Power = Voltage^2 / Resistance
Power = 220 * 220 / 70.533
Power = 686.2004 Watt.
For your knowledge
Power = Voltage * Current
Power = Voltage^2 / Resistance
We used the second formula because resistance was given constant.
As resistance is given constant.
750 = 230 * 230 / Resistance
Resistance = 230 * 230 / 750
Resistance = 70.533
If it is used with mains potential difference of only 220 V then
Power = Voltage^2 / Resistance
Power = 220 * 220 / 70.533
Power = 686.2004 Watt.
For your knowledge
Power = Voltage * Current
Power = Voltage^2 / Resistance
We used the second formula because resistance was given constant.
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