Question

an iron nail is suspended in copper sulphate in test tube 1 and copper wire is diped in test tube 2.the tubes left undisturbed for 20 minutes what will happen to cuso4 solution in test tube 1..? What will happen to copper wire and ferrous sulphate solution in test tube 2 ? What will happen to iron nail in test tube 1​

Answer 1

Answer:

The displacement reaction taking place can e written as :

Fe + CuSO4(aq) == FeSO4 + Cu

Iron + Copper Sulphate(aq) == Iron sulphate + copper

Now, enough basics, directly to question…

A fter 30 minutes:

1) The initial blue colour of copper sulphate solution is changed to light green colour of iron sulphate.

2) The initial silver colour of iron nail is changed to reddish-brown colour due to coating of copper metal on the nail.

Explanation:

Hope it helps

Answer 2

Explanation:

in test tube 1

this reaction takes place

CuSO4 +Fe=FeSO4+Cu

in test tube 2

no reaction because iron is more reactive than copper