An iron of length 1 m and diameter 4 cm is melted and cast into thin wires of length 20 cm each.
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The required radius of each thin wire is 0.1 m
Step-by-step explanation:
Correct statement:
An iron of length 1 m and diameter 4 cm is melted and cast into thin wires of length 20 cm each. If the number of such wires be 2000, find the radius of each thin wire.
Given data:
Length of iron = 1 m
Diameter of iron rd = 4 cm = 0.4 m
Length of thin wires = 20 cm = 0.2 m
The volume of the iron rod of radius 4/2 cm = 2 cm is π x 22 x 100 cm^3
The volume of each thin wire = πr^2 x 20
We have = π x 2^2 x 100 = 2000 x πr^2 x 20
=> 40 r^2 = 4 => r^2 = 1/100
r = 1/10 cm = 0.1 m
Thus the required radius of each thin wire is 0.1 m
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