Math, asked by sanjithkumar4119, 10 months ago

An iron of length 1 m and diameter 4 cm is melted and cast into thin wires of length 20 cm each.

Answers

Answered by Fatimakincsem
2

The required radius of each thin wire is 0.1 m

Step-by-step explanation:

Correct statement:

An iron of length 1 m and diameter 4 cm is melted and cast into thin wires of length 20 cm each. If the number of such wires be 2000, find the radius of each thin wire.

Given data:

Length of iron = 1 m

Diameter of iron rd = 4 cm = 0.4 m

Length of thin wires = 20 cm = 0.2 m

The volume of the iron rod of radius 4/2 cm = 2 cm is π x 22 x 100 cm^3  

The volume of each thin wire = πr^2 x 20

We have = π x 2^2 x 100 = 2000 x πr^2 x 20

=> 40 r^2 = 4 => r^2 = 1/100

r = 1/10 cm = 0.1 m

Thus the required radius of each thin wire is 0.1 m

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