Chemistry, asked by Diya5850, 1 year ago

An iron ore sample is found to be 35.00% fe by mass. how many grams of ore are needed to obtain 454.0 of fe?

Answers

Answered by Deepsbhargav
25
hey dear!!!? here is your answer

In simple mathematics,

100x454/35=1297.142857 grams of iron ore is needed. ____(answer)

But practically it may not be possible to get yield of 100%. So if yield % is given then multiply by it.

hope it will help you..

For example in this case if yield percentage is A%,

then ore needed will be

=1297.142857x A/100 grams
Answered by CreAzieStsoUl
2

Explanation:

ᴛʜɪs ᴍᴀʏ ʜᴇʟᴘ ʏᴏᴜ ᴛᴏ ᴜɴᴅᴇʀsᴛᴀɴᴅ..........

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