An iron ore sample is found to be 35.00% fe by mass. how many grams of ore are needed to obtain 454.0 of fe?
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Answered by
25
hey dear!!!? here is your answer
In simple mathematics,
100x454/35=1297.142857 grams of iron ore is needed. ____(answer)
But practically it may not be possible to get yield of 100%. So if yield % is given then multiply by it.
hope it will help you..
For example in this case if yield percentage is A%,
then ore needed will be
=1297.142857x A/100 grams
In simple mathematics,
100x454/35=1297.142857 grams of iron ore is needed. ____(answer)
But practically it may not be possible to get yield of 100%. So if yield % is given then multiply by it.
hope it will help you..
For example in this case if yield percentage is A%,
then ore needed will be
=1297.142857x A/100 grams
Answered by
2
Explanation:
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