An iron ore sample is impure Fe2O3. When Fe2O3 is heated with an excess of carbon, iron m
is produced as per the following equation:
Fe2O3(s) + 3C(s) + 2Fe(s) + 3 CO(g)
From a sample of ore weighing 752 kg, 453 kg of pure iron was obtained. What is the percentage
of Fe2O3 in the ore sample
utkarsh498:
done mate
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Answer:
Explanation:
Weight of sample- 752 kg.
Weight of iron- 453 kg.
Weight of Fe2O3= 453*159.69/255.85
=> 647.62...
% of Fe2O3= 647.62/752*100...
=> 86.11%.
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