An iron pillar consists of a cylinder portion of 2.8 meters height and 20 cm in diameter and a cone of 42 cm height surmounting it . Find the weight of the pillar if 1 cm³ of iron weighs 7.5 .
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★Answer:–
It is given that
→Height of the cylinder = 2.8m = 280cm
→ Diameter of the cylinder = 20c
→ Radius of the cylinder = 20/2 = 10cm
→ Height of the cone = 42cm
We know that
★Volume of the pillar = πr2h + 1/3 πr2H
It can be written as
★Volume of the pillar = πr2 (h + 1/3H)
By substituting the values
Volume of the pillar = (22/7) × 102 (280 + (1/3 × 42))
On further calculation
Volume of the pillar = 2200/7 × (280 + 14) = 92400 cm3
So the weight of pillar = (92400 × 7.5)/ 1000 = 693kg
Therefore, the weight of the pillar is 693kg.
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