An iron pillar consists of a cylindrical
portion of 2.8 m height and 20cm in
diameter and a cone of 42 cm height
surmounting it. Find the weight of the
pillar if lem of iron weighs 7.5 gram.
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Answer:
answer is 693 kg of the pillar
Step-by-step explanation:
height of cylinder = 2.8m= 280cm
radius of cylinder = 20/2= 10
- volume of cylinder = πr^2h = 22/7*10*10*280
= 88000 cm^3
height of cone = 42cm
radius of cone = 10 cm
- volume of cone = 1/3πr^2h=1/3*22/7*10*10*42= 4400 cm^3
- total volume of iron pillar =
volume of cone + volume of cylinder
4400 + 88000 = 92400 cm^3
- weight of 1cm^3 of iron pillar so in kg
7.5/1000*92400= 693kg
I hope that may help you.
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