an iron pillar has some part in the form of a right circular cylinder and remaining in the form of right circular conethe radius of base of each of cone on cylinder is its the cylindrical part is 240cm high and conical part is 36 find the weight of the pillar if one cubic centimetre of iron weight 7.8 grams with figure
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Answered by
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Step-by-step explanation:
Q:-solve and verify the equation
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cancelling 6( R.H.S) By 3 From L.H.S
CHECK:-
THEREFORE,L.H.S=R.H.S
VERIFIED✔️
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HOPE IT HELPS YOU..
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Answer:
Step-by-step explanation:
We know that:-
Volume of cylinder = πr²h
Volume of cone = ⅓πr²h
Now,
Volume of cylinder = 3.14 × 8 × 8 × 240
=> 48320.4 cm^3
Now,
⅓ × 3.14 × 8 × 8 × 36
1 × 3.14 × 8 × 8 × 12
3.14 × 64 ×12
2411.52 cm^3
Now,
W = 48320.4 + 2411.52
W = 50730
Now,
1kg = 1000gm
7.8/1000 × 50730
0.0078 × 50730
395.4 kg
Weight of pillar is 395 kg.
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