Art, asked by soviet35, 3 months ago

An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of the base of each of cone and cylinder is 8 cm. The cylinderical part is 240 cm high and the conical part in 36 cm high. Find the weight of the pillar if one cu. cm of iron weighs 7.8 grams.​

Answers

Answered by PD626471
11

Answer

{\textsf{\textbf{\pink{\underline{Given:- }}}}}

  • Radius = 8 cm
  • Height of cylinder = 240 cm
  • the conical part in 36 cm high.

{\textsf{\textbf{\purple{\underline{To find:- }}}}}

Weight of the pillar if one cu. cm of iron weighs 7.8 grams.

{\textsf{\textbf{\orange{\underline{ Solution :- }}}}}

{\textsf{\textbf{\blue{\underline{ We know that }}}}}

  • Volume of cylinder = πr²h
  • Volume of cone = ⅓πr²h

Now,

Volume of cylinder = 3.14 × 8 × 8 × 240

=> 48320.4 cm^3

Now,

  • ⅓ × 3.14 × 8 × 8 × 36
  • 1 × 3.14 × 8 × 8 × 12
  • 3.14 × 64 ×12
  • 2411.52 cm^3

Now,

Weight of pillar = Volume of cylinder + volume of cone

  • W = 48320.4 + 2411.52
  • W = 50730

Now,

  • 1kg = 1000gm
  • 7.8/1000 × 50730
  • 0.0078 × 50730
  • 395.4 kg

{\textsf{\textbf{\pink{\underline{Weight of pillar is 395 kg.}}}}}

Answered by Anonymous
0

Answer:

395 \: kg

Explanation:

We know that:-

Volume of cylinder = πr²h

Volume of cone = ⅓πr²h

Now,

Volume of cylinder = 3.14 × 8 × 8 × 240

=> 48320.4 cm^3

Now,

⅓ × 3.14 × 8 × 8 × 36

1 × 3.14 × 8 × 8 × 12

3.14 × 64 ×12

2411.52 cm^3

Now,

W = 48320.4 + 2411.52

W = 50730

Now,

1kg = 1000gm

7.8/1000 × 50730

0.0078 × 50730

395.4 kg

Weight of pillar is 395 kg.

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