An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of the base of each of cone and cylinder is 8 cm. The cylinderical part is 240 cm high and the conical part in 36 cm high. Find the weight of the pillar if one cu. cm of iron weighs 7.8 grams.
Answers
Answer:
GIVEN
Radius = 8 cm
Height of cylinder = 240 cm
The conical part in 36 cm high..
TO FIND
Weight of the pillar if one cu. cm of iron weighs 7.8 grams.
SOLUTION ✍
We know that
Volume of cylinder = πr²h
Volume of cone = ⅓πr²h
Volume of cylinder
= 3.14 × 8 × 8 × 240
= 48320.4 cm³
Volume of cone
= ⅓ × 3.14 × 8 × 8 × 36
= 1 × 3.14 × 8 × 8 × 12
= 3.14 × 64 ×12
= 2411.52 cm³
Weight of pillar = Volume of cylinder + volume of cone
W = 48320.4 + 2411.52
W = 50730
1kg = 1000gm
7.8/1000 × 50730
0.0078 × 50730
395.4 kg
✨ Weight of pillar is 395 kg
Explanation:
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Answer:
Explanation:
We know that:-
Volume of cylinder = πr²h
Volume of cone = ⅓πr²h
Now,
Volume of cylinder = 3.14 × 8 × 8 × 240
=> 48320.4 cm^3
Now,
⅓ × 3.14 × 8 × 8 × 36
1 × 3.14 × 8 × 8 × 12
3.14 × 64 ×12
2411.52 cm^3
Now,
W = 48320.4 + 2411.52
W = 50730
Now,
1kg = 1000gm
7.8/1000 × 50730
0.0078 × 50730
395.4 kg
Weight of pillar is 395 kg.