CBSE BOARD X, asked by virtuoso10, 2 months ago

An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of the base of each of cone and cylinder is 8 cm. The cylinderical part is 240 cm high and the conical part in 36 cm high. Find the weight of the pillar if one cu. cm of iron weighs 7.8 grams.​

Answers

Answered by abhishek917211
10

The weight of the pillar if one cu. Cm of iron weighs 7.8 grams. is  395366.322 g

Step-by-step explanation:

Height of cylinder = 240 cm

Volume of cylinder =

Radius of cylinder = 8 cm

\pi r^2 h

\frac{22}{7} \times (8)^2 (240)

Volume of cylinder =

Volume of cylinder =

Height of cone =36 cm

Radius of cone = 8 cm

Volume of cone =

\frac{1}{3} \pi r^2 h

Volume of cone =

2413.7142 cm^3

Volume of cone =

Total volume of pillar = Volume of cone + Volume of cylinder

Total volume of pillar = 2413.7142 + 48274.2857 = 50687.99

Answered by OoINTROVERToO
8

GIVEN

  • Radius = 8 cm
  • Height of cylinder = 240 cm
  • The conical part in 36 cm high.

TO FIND

  • Weight of the pillar if one cu. cm of iron weighs 7.8 grams.

SOLUTION ✍

We know that

  • Volume of cylinder = πr²h
  • Volume of cone = ⅓πr²h

Volume of cylinder

= 3.14 × 8 × 8 × 240

= 48320.4 cm³

Volume of cone

= ⅓ × 3.14 × 8 × 8 × 36

= 1 × 3.14 × 8 × 8 × 12

= 3.14 × 64 ×12

= 2411.52 cm³

Now,

Weight of pillar = Volume of cylinder + volume of cone

W = 48320.4 + 2411.52

W = 50730

1kg = 1000gm

7.8/1000 × 50730

0.0078 × 50730

395.4 kg

Weight of pillar is 395 kg

▬▬▬▬▬▬▬▬▬▬▬▬▬

Similar questions