Question

an Iron Pillar has some part in the form of cylinder meaning form of a right circular cone the radius of the base of each of cone and cylinder rates and unit of the cylindrical part is 240 cm high and the conical part is 36 and M height find the weight of the pillar if the one cubic CM of iron weights and 7.8 gram

Answer 1

The volume of the cylindrical part = πr²h
                                                      = 22/7 x 8² x 240 = 48274 2/7 cm³

The volume of the conical part = 1/3 x base area x height
                                                 = 1/3 x 22/7 x 8² x 36 
                                                 = 2413  5/7 cm³

Total volume = 48274 2/7  + 2413  5/7 = 50688 cm³

Mass = Density x Volume
          = 7.5 x 50688
          = 380160g
          = 380.16 kg

If you want the weight in Newtons, we assume that the gravitational force g = 10N/kg

The weight = 380.16 x 10 = 3801.6 N


please mark BRAINLIEST

Answer 2

Answer:

$395 \: kg$

Step-by-step explanation:

We know that:-

Volume of cylinder = πr²h

Volume of cone = ⅓πr²h

Now,

Volume of cylinder = 3.14 × 8 × 8 × 240

=> 48320.4 cm^3

Now,

⅓ × 3.14 × 8 × 8 × 36

1 × 3.14 × 8 × 8 × 12

3.14 × 64 ×12

2411.52 cm^3

Now,

W = 48320.4 + 2411.52

W = 50730

Now,

1kg = 1000gm

7.8/1000 × 50730

0.0078 × 50730

395.4 kg

Weight of pillar is 395 kg.