an iron pipe 20 cm long has external diameter equal to 20 CM if the thickness of the pipe is 1 m find the whole surface of the pipe
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Though your question is incorrect. I think the thickness must be equal to 1 cm.
External radius(R)=10 cm
Internal radius(r)=10-1=9cm
length of pipe = 20 cm
Whole surface are = 2*pi*r*h + 2*pi*R*h+2*pi*(R^2-r^2)
=2*pi(r*h + R*h +(R-r)(R+r)
2×22/7(180+200+19)
2*22/7*(409)
=17996/7
=2570.85 cm^2
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i got this answer.....
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