an iron Pipe 20 cm long has external diameter equal
to 25 cm. If the thickness of the pipe is 1 cm, find
the whole surface of the pipe.
Answers
Answered by
29
Answer:
Height of pipe = 20 cm
External diameter = 25 cm
External radius = 25/2 = 12.5 cm
Internal diameter = 25 - (1 + 1)
= 23 cm
Internal radius = 23/2 = 11.5 cm
Let the external radius be R and the internal radius be r.
Total surface area of the pipe = 2πh(R + r) + 2π(R² - r²)
⇒ 2*22/7*20(12.5 + 11.5) + 2*22/7*{(12.5)² - (11.5²)
⇒ (44*480)/7 + (44*24)/7
⇒ 21120/7 + 1056/7
⇒ 22176/7
= 3168 cm²
So, the total surface area of the pipe is 3168 square cm.
Answered by
1
Total Surface Area
= 2πh(R+r) + 2π(R²-r²)
- Putting the given value in above formula , we get
= 3168 cm²
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