an iron pipe 20 cm long has extirior diameter equals to 25 CM if the thickness of the pipe in 1 cm find the total surface of the pipe?
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Length of pipe h = 20 cm
Exterior diameter = 25 cm
exterior radius of pipe R = 25÷ 2
= 12.5cm
interior diameter= 25 - thickness
25 - 1 = 24 cm,
Interior radius r = 24 ÷ 2 = 12cm
Interior and exterior c.s.a
= 2πrh + 2πRh = 2πh ( r + R)
=2×(22/ 7) ×20 (12 + 12.5) = 3080cm^2
area of upper and lower ring portion of the pipe
= exterior surface area - interior surface area
=2πR^2 - 2πr^2 = 2π ( R^2 - r^2)
= 44/ 7 [ (12.5)^2 - (12)^2 ]
= 77cm^2
Total surface area = 3080 + 77
= 3157cm^2
Answer:total surface area = 3157cm^2
Exterior diameter = 25 cm
exterior radius of pipe R = 25÷ 2
= 12.5cm
interior diameter= 25 - thickness
25 - 1 = 24 cm,
Interior radius r = 24 ÷ 2 = 12cm
Interior and exterior c.s.a
= 2πrh + 2πRh = 2πh ( r + R)
=2×(22/ 7) ×20 (12 + 12.5) = 3080cm^2
area of upper and lower ring portion of the pipe
= exterior surface area - interior surface area
=2πR^2 - 2πr^2 = 2π ( R^2 - r^2)
= 44/ 7 [ (12.5)^2 - (12)^2 ]
= 77cm^2
Total surface area = 3080 + 77
= 3157cm^2
Answer:total surface area = 3157cm^2
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