Math, asked by uvjindal72, 10 days ago

An iron pipe is 0.35 m long and its interior diameter is 8 cm . If the
thickness of the pipe is 1cm and iron weight is 8 g/cm^3 , find the weight of pipe

Answers

Answered by chhyaabhang99
0

AnswerLet external diameter be d  

2

 and internal be d  

1

 

⇒d  

2

=8cm & d  

1

=8−1−1=6cm

Therefore, r  

1

=3cm & r  

2

=4cm

Volume of hollow cylindrical pipe=π(r  

2

2

−r  

1

2

)×h

=  

7

22

((4)  

2

−(3)  

2

)×21

=  

7

22

×7×21

=462cm  

3

 

∴Weight of the pipe=8×462=3696g=3.696kg:

Step-by-step explanation:

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