an iron pipe is 14cm long and its external diameter is 10 cm . If thickness of the pipe is 1cm and iron weight 8g/cm³. Find the weigth of the pipe.
Answers
Answered by
0
Answer:
given that,
external diameter = 8 cm
external radius = R =4 cm
thickness= 1 cm
so, internal diameter= (8-1) cm = 7 cm
internal radius = r = 3.5 cm
volume of iron = π(R²- r²)h
= > \frac{22}{7}( {4}^{2} - {3.5}^{2} )21=>
7
22
(4
2
−3.5
2
)21
=> 247.5 cm³
weight of iron = 247.5× 8 = 1980 gram or 1.98 kg
Similar questions