An iron pipe is 21 cm long and its external diameter is 8cm. If its thickness is 1cm and the iron weighs 8gm/cm^3, find the weight of the pipe
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Answer:
Step-by-step explanation:
the pipe is a cyclindrical object
external radius = 8cm
internal radius = 8-1 = 7cm
volume of the thickness = external cyclinder volume - internal cyclinder volum
= πr²h) external - πr²h)internal
height = 21 cm
= π8²×21 - π7²×21
= 21π (64-49)
= 21π×15 = 21×22×15/7 = 3×22×15 = 990cm³
iron weighs = 8gm/cm³
990×8 = 7920 gram = 7.92 kg
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