An iron pipe is 21 m long and it's exterior diameter is 8 cm if the thickness of pipe is 1 cm and iron weight is 8g/cubic cm find the weight of pipe
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672
lenght=21m=21*100=2100cm which is height (* means multiplied)
exterior diameter=8cm
radius=d/2
=8/2
=4cm
let us take exteror radius as R
thickness=1cm
iterior radius=exteriror(outer) radius-thickness
=4-1
=3cm(let inner radius be r
volume of pipe (which is hollow)=π(R squrae-r squrae)*height
=22/7(4 squrae-3 squrae)*2100
=22/7(16-9)*2100
=22/7*7*2100
=46200cubic cm
weight = 46200*8
=369600gram
=369.6kilogram
exterior diameter=8cm
radius=d/2
=8/2
=4cm
let us take exteror radius as R
thickness=1cm
iterior radius=exteriror(outer) radius-thickness
=4-1
=3cm(let inner radius be r
volume of pipe (which is hollow)=π(R squrae-r squrae)*height
=22/7(4 squrae-3 squrae)*2100
=22/7(16-9)*2100
=22/7*7*2100
=46200cubic cm
weight = 46200*8
=369600gram
=369.6kilogram
aaryan13:
if it is wrong let me know
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Answer:
Answer of chapter mesuration
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