An iron pipe is 21 m long and its exterior diameter is 8 cm. If the thickness of the
pipe is 1 cm and iron weight is 8 g/cm?, find the weight of pipe.
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2
Let external diameter be d
2
and internal be d
1
⇒d
2
=8cm & d
1
=8−1−1=6cm
Therefore, r
1
=3cm & r
2
=4cm
Volume of hollow cylindrical pipe=π(r
2
2
−r
1
2
)×h
=
7
22
((4)
2
−(3)
2
)×21
=
7
22
×7×21
=462cm
3
∴Weight of the pipe=8×462=3696g=3.696kg
2
and internal be d
1
⇒d
2
=8cm & d
1
=8−1−1=6cm
Therefore, r
1
=3cm & r
2
=4cm
Volume of hollow cylindrical pipe=π(r
2
2
−r
1
2
)×h
=
7
22
((4)
2
−(3)
2
)×21
=
7
22
×7×21
=462cm
3
∴Weight of the pipe=8×462=3696g=3.696kg
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