Question

An iron pipe is 21 m long and its exterior diameter is 8 cm. If the thickness of the
pipe is 1 cm and iron weight is 8 g/cm, find the weight of pipe.​

Answer 1

Step-by-step explanation:

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Answer 2

Let external diameter be $D_2$ =8cm & $D_1$ =8−1−1=6cm

⇒ $D_2$ 8cm & $D_1$=8−1−1=6cm

⇒Therefore, $r_1$ =3cm & $r_2$ =4cm

Volume of hollow cylindrical pipe=

⇒π( $r²_2 - r²_1$ ) × h

⇒$\bold{\dfrac{22}{7} ((4)² −(3)²))× 21}$

$\bold{\dfrac{22}{7}×7×21}$

=462cm³

${\boxed{\sf{\red{∴Weight\ of\ the\ pipe=8×462=3696g=3.696kg</p><p>}}}}$

3.696kg answer

hope it helps ☺️☺️