Question

An Iron pipe of length 5 (1 by 3) metres long was cut into two pieces one piece was 3 (1 by 7) long what is the length of the Other piece?

​

Answer 1

Answer:

$\frac{46}{21}$ = $2\frac{4}{21}$

Step-by-step explanation:

total length =  $5\frac{1}{3} m$ = $\frac{16}{3}$m

number of pieces = 2

1st piece = $3 \frac{1}{7}$ m = $\frac{22}{7}$m

2nd piece =  $\frac{16}{3}$- $\frac{22}{7}$

LCM = 21

$\frac{112-66}{21}$

= $\frac{46}{21}$ = $2\frac{4}{21}$m