Question

An iron pole consists of a cylinder of height 240 cm and base diameter 26 cm, which is surmounted by another cylinder of height 66 cm and radius 10 cm. Find the mass of the pole, given that 1cm³ of iron has approximately 8 g mass. [Use π = 3.14]

Answer 1

SOLUTION:
[FIGURE IS IN THE ATTACHMENT]

An iron pole is a combination of two cylinders.

For first cylinder:
Height (h)= 240 cm
Base diameter= 26 cm
Base radius(r)= 26/2= 13 cm

For second cylinder:
Height= 66 cm
Radius= 10 cm

Volume of Cylinder= πr²h

Total volume of iron pole= volume of first cylinder + volume of second cylinder

= π(13)²× 240 +π (10)²× 66
= π[169×240 + 100× 66]
= 3.14[40560+6600]
= 3.14× 47160= 148082.4 cm³

Total mass of the iron pole= 148082.4× 8 g = 1184659.2 g

[Given : 1 cm³= 8 g]
= 1184659.2/1000 kg= 1184.66 kg
[ 1 g= 1/1000 kg]

Hence,total mass of the iron pole= 1184.66 kg

HOPE THIS WILL HELP YOU....

Answer 2

Answer:

here is your answer l hope you get it