An iron pole is 4 m high and 28 cm in diameter. Find its weight if the iron weighs 5 g per m³
Answers
Answered by
1
Answer:
1232 Kg
Step-by-step explanation:
Radius = Diameter/2=28/2=14
4m =400cm
volume = πr²h
22/7x14x14x400
22x2x14x400
=246400m³
WEIGHT = 246400x5
=1232000g or 1232Kg
Answered by
1
Given :-
- Height of iron pole = 4 m.
- Diameter of the iron pole = 28 cm.
To Find :-
- Weight of the iron pole.
Solution :-
- Radius of the pole :-
➩ 28/2
➩ 14 cm
Converting centimeter to meters ↓
➩ 14/100
➩ 0.14 m.
Volume of the iron pole :-
2 h
➩ 22/7 × 0.14 × 0.14 × 4
➩ 22 × 0.02 × 0.14 × 4
➩ 0.2464 m^3.
Weight of the pole :-
- ➩ Volume × weight per volume.
- ➩ 0.2464 × 50
- ➩ 12.32 kg
Mark ❤️
Similar questions