Question

an Iron Pole is 4 metre high and 28 CM in diameter. find its weight if the iron weighs 50 kg per m³​

Answer 1

⭐《ANSWER》

↪Actually welcome to the concept of the MEASUREMENTS

$\huge\mathfrak\red {aNsWeR}$

↪Since here above given , basically we have to calculate the volume of the pole and then arrange it to get the weight of it

↪So as here, Radius "r" = 28/2 = 14 cm = 14/100 = 0.14 mtrs

↪Height "h" = 4 m

〽VOLUME OF THE POLE = pi r^2 h

↪Volume = 22/7 * 0.14 * 0.14 * 4

↪Volume = 22 * 0.02 * 0.14 *4 = 0.2464 m^3

↪thus the Volume is = 0.2464 m^3

↪thus here , weight = volume × weight per volume

〽thus , Weight = 0.2464 * 50 = 12.32 kg

$\huge\mathfrak\red {WEIGHT = 12.32 Kg}$

Answer 2

↗HeyA User

↗The pole is in eqvilant to a STRUCTURE of pipe , therefore we calculate here the Volume of the pole

↗So as here, Radius "r" = 28/2 = 14 cm = 14/100 = 0.14 mtrs

eight "h" = 4 m

↗VOLUME OF THE POLE = pi r^2 h

↗Volume = 22/7 * 0.14 * 0.14 * 4

↗Volume = 22 * 0.02 * 0.14 *4 = 0.2464 m^3 thus the Volume is = 0.2464 m^3

↗ Therefore here the above expression is given as that ,

↗WEIGHT = Volume × per unit weight

⚠thus , Weight = 0.2464 * 50 = 12.32 kg⚠