Physics, asked by svsmanya200771, 10 months ago

An iron ring of 1.20m in diameter is to be put on a wooden cart wheel. The diameter of this wheel is 1.0 cm greater than that of the ring. The temperature of the ring that must be raised before it slips on the wooden wheel is (coefficient of linear expansion of iron =12?10 power -6 degree centigrade).

Answers

Answered by satyavathilamps
2

Answer:

Explanation:

Thermal Expansion Coefficients at 20 C

Material Fractional expansion per degree C x10^-6 Fractional expansion per degree F x10^-6

Brass 19 11

Copper 17 9.4

Iron 12 6.7

Steel 13 7.2                                                                                                    Multiply the temperature change by 7.2 x 10-6, which is the expansion coefficient for steel. Continuing the example, you would multiply 0.0000072 by 5 to get 0.000036. Multiply the product of the expansion coefficient and the temperature increase by the original length of the steel                                                                                        

Answered by tentusatyapoli
1

Answer:

Explanation:

Thermal Expansion Coefficients at 20 C

Material Fractional expansion per degree C x10^-6 Fractional expansion per degree F x10^-6

Brass 19 11

Copper 17 9.4

Iron 12 6.7

Steel 13 7.2                                                                                                    Multiply the temperature change by 7.2 x 10-6, which is the expansion coefficient for steel. Continuing the example, you would multiply 0.0000072 by 5 to get 0.000036. Multiply the product of the expansion coefficient and the temperature increase by the original length of the steel            

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